how would you solve this:
12^x x 3^3x =18
12x x 33x = 18
thanks!
Solve for x
3^(4 x) 4^x = 18
Factor out the common power x from the left hand side:
324^x = 18
Take the logarithm base 324 of both sides:
x = 1/2
+33616 Since 12 = 22*3 we can write 12x*33x=18 as 22x*34x=21*32
Divide both sides by 21*32 to get 2(2x-1)*3(4x-2)=1 or 2(2x-1)*3(4x-2)=1 or
2(2x-1)*32(2x-1)=1 or (2*32)(2x-1) = 1 or 18(2x-1) = 1
Now the only way 18 to some power can equal 1 is if that power is zero. Hence 2x - 1 = 0
so x = 1/2
