Inequalities

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How do you solve \(x^3-3x\le0\)

Reflec Jan 6, 2021

edited by Reflec Jan 6, 2021

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2⁺⁰ Answers

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\(x^3<=3x, x^2=3, x=\pm\sqrt3\), hope this helped :)

TC072 Jan 6, 2021

+41

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Thanks

Reflec Jan 6, 2021

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