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How do you solve \(x^3-3x\le0\)

 Jan 6, 2021
edited by Reflec  Jan 6, 2021
 #1
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\(x^3<=3x, x^2=3, x=\pm\sqrt3\), hope this helped :)

 Jan 6, 2021
 #2
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Thanks

smiley

Reflec  Jan 6, 2021

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