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Solve the inequality k^2 - 7k + 12.25 > 0.

 Jun 15, 2022

Best Answer 

 #1
avatar+514 
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Let's solve this!

\(k^2-7k+12.25>0\)

\(\left(k-3.5\right)^2>0\)

\(k-3.5<0\quad \mathrm{or}\quad \:k-3.5>0\)

\(\begin{bmatrix}\mathrm{Solution:}\:&\:k<3.5\quad \mathrm{or}\quad \:k>3.5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:3.5\right)\cup \left(3.5,\:\infty \:\right)\end{bmatrix}\)

Hope this helps!

 Jun 15, 2022
 #1
avatar+514 
+2
Best Answer

Let's solve this!

\(k^2-7k+12.25>0\)

\(\left(k-3.5\right)^2>0\)

\(k-3.5<0\quad \mathrm{or}\quad \:k-3.5>0\)

\(\begin{bmatrix}\mathrm{Solution:}\:&\:k<3.5\quad \mathrm{or}\quad \:k>3.5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:3.5\right)\cup \left(3.5,\:\infty \:\right)\end{bmatrix}\)

Hope this helps!

mworkhard222 Jun 15, 2022

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