Solve the inequality 2x - 5 <= -x + 12 - 3x + 19 Give the answer as a interval.
\(2x-5\le \:-x+12-3x+19\)
\(2x-5\le \:-x-3x+12+19\)
\(2x-5\le \:-4x+12+19\)
\(2x-5\le \:-4x+31\)
\(2x\le \:-4x+36\)
\(6x\le \:36\)
\(x\le \:6\)
Interval notation: \((-\infty \:,\:6]\)
-Vinculum
