+0  
 
0
48
1
avatar

Solve the inequality 2x - 5 <= -x + 12 - 3x + 19  Give the answer as a interval.

 Jul 24, 2022
 #1
avatar+578 
+1

\(2x-5\le \:-x+12-3x+19\)

 

\(2x-5\le \:-x-3x+12+19\)

 

\(2x-5\le \:-4x+12+19\)

 

\(2x-5\le \:-4x+31\)

 

\(2x\le \:-4x+36\)

 

\(6x\le \:36\)

 

\(x\le \:6\)

 

Interval notation: \((-\infty \:,\:6]\)

 

-Vinculum

 Jul 24, 2022

21 Online Users