+515 \(\frac{1}{3}\cdot t-5
\(\frac{1}{3}t
\(-\frac{2}{3}t<3\)
\(\frac{2}{3}t>-3\)
\(2t>-9\)
\(t>-\frac{9}{2}\)
So in interval notation: \(\left(-\frac{9}{2},\:\infty \:\right)\)
+515 idk why the first 2 lines are not showing up, it's supposed to say:
\(\frac{1}{3}\cdot \:t-5<\:t-2\)
\(\frac{1}{3}t
+515 umm??? still the second line is not working. it says:
(1/3)t < t + 3
