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Solve 1/3*t - 5 < t - 2.  Give your answer as an interval.

 Jun 29, 2021
 #1
avatar+493 
+3

\(\frac{1}{3}\cdot t-5

 

\(\frac{1}{3}t

 

\(-\frac{2}{3}t<3\)

 

\(\frac{2}{3}t>-3\)

 

\(2t>-9\)

 

\(t>-\frac{9}{2}\)

 

 

 

So in interval notation: \(\left(-\frac{9}{2},\:\infty \:\right)\)

 Jun 29, 2021
edited by mworkhard222  Jun 29, 2021
edited by mworkhard222  Jun 29, 2021
 #2
avatar+493 
+3

idk why the first 2 lines are not showing up, it's supposed to say:

 

\(\frac{1}{3}\cdot \:t-5<\:t-2\)

 

\(\frac{1}{3}t

mworkhard222  Jun 29, 2021
edited by mworkhard222  Jun 29, 2021
 #3
avatar+493 
+3

umm??? still the second line is not working. it says:

 

(1/3)t < t + 3

mworkhard222  Jun 29, 2021

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