Solve \(\frac{1}{3}t-5 . \)
From isolating \(t\), we get \(-\frac{2}{3}t<3\). Then, by multiplying \(-\frac{3}{2}\), the inequality becomes \(t>-\frac{9}{2}\). (Be careful to switch the inequality sign!)
Therefore, in interval notation, the answer is \((-\frac{9}{2},\infty)\)