Inequality

$8+x<4-3x-7<5x-4+11$

$8+x<4-3x-7\quad \mathrm{and}\quad \:4-3x-7<5x-4+11$

$x<-\frac{11}{4}\quad \mathrm{and}\quad \:x>-\frac{5}{4}$

Since they are overlapping intervals:

No Solution

-Vinculum