Solve the inequality 8 + x < 4 - 3x - 7 < 5x - 4+ 11.
\(8+x<4-3x-7<5x-4+11\)
\(8+x<4-3x-7\quad \mathrm{and}\quad \:4-3x-7<5x-4+11\)
\(x<-\frac{11}{4}\quad \mathrm{and}\quad \:x>-\frac{5}{4}\)
Since they are overlapping intervals:
No Solution
-Vinculum