+129899 Remember, smoky......an inscribed angle = 1/2 of its intercepted arc...
10. 5x + 4 = (1/2)(208)
5x + 4 = 104 subtract 4 from both sides
5x = 100 divide by 5 on each side
x = 20
2. Notice that if we connected A and B, we would have an isosceles triangle.....and each base angle would equal [ 180 - 48] / 2 = 132/2 = 66° = angle BAC = angle ABC
So angle BAC = [1/2] x°
66 = (1/2)x multiply both sides by 2
132° = x
7. The 90° angle in the right triangle intercepts an arc of twice its measure.....therefore, x = 180°
And since the other two sides of the right triangle are equal, the angles opposite those sides are equal, too.....so each angle = 45° and each intercepts an arc twice its measure.....therefore, y = 90°
+129899 Remember, smoky......an inscribed angle = 1/2 of its intercepted arc...
10. 5x + 4 = (1/2)(208)
5x + 4 = 104 subtract 4 from both sides
5x = 100 divide by 5 on each side
x = 20
2. Notice that if we connected A and B, we would have an isosceles triangle.....and each base angle would equal [ 180 - 48] / 2 = 132/2 = 66° = angle BAC = angle ABC
So angle BAC = [1/2] x°
66 = (1/2)x multiply both sides by 2
132° = x
7. The 90° angle in the right triangle intercepts an arc of twice its measure.....therefore, x = 180°
And since the other two sides of the right triangle are equal, the angles opposite those sides are equal, too.....so each angle = 45° and each intercepts an arc twice its measure.....therefore, y = 90°
