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Find the value of each variable 

 Feb 4, 2016
edited by Guest  Feb 4, 2016

Best Answer 

 #2
avatar+129852 
+5

Remember, smoky......an inscribed angle = 1/2 of its intercepted arc...

 

10.    5x + 4 =   (1/2)(208)

         5x + 4 =  104      subtract 4 from both sides

         5x  = 100       divide by 5 on each side

          x  = 20

 

2.   Notice that if we connected A and B, we would have an isosceles triangle.....and each base angle would equal    [ 180  - 48] / 2   =  132/2  =  66°  = angle BAC = angle ABC

 

So   angle BAC  =  [1/2] x°

 

66 = (1/2)x     multiply both sides by 2

 

132°  = x

 

 

7.   The  90° angle in the right triangle intercepts an arc of twice its measure.....therefore,  x = 180°

 

And since the other two sides of the right triangle are equal, the angles opposite those sides are equal, too.....so  each angle = 45°  and each intercepts an arc twice its measure.....therefore, y = 90°

 

 

cool cool cool

 Feb 4, 2016
 #1
avatar+77 
0

the varieable is x and y

 Feb 4, 2016
 #2
avatar+129852 
+5
Best Answer

Remember, smoky......an inscribed angle = 1/2 of its intercepted arc...

 

10.    5x + 4 =   (1/2)(208)

         5x + 4 =  104      subtract 4 from both sides

         5x  = 100       divide by 5 on each side

          x  = 20

 

2.   Notice that if we connected A and B, we would have an isosceles triangle.....and each base angle would equal    [ 180  - 48] / 2   =  132/2  =  66°  = angle BAC = angle ABC

 

So   angle BAC  =  [1/2] x°

 

66 = (1/2)x     multiply both sides by 2

 

132°  = x

 

 

7.   The  90° angle in the right triangle intercepts an arc of twice its measure.....therefore,  x = 180°

 

And since the other two sides of the right triangle are equal, the angles opposite those sides are equal, too.....so  each angle = 45°  and each intercepts an arc twice its measure.....therefore, y = 90°

 

 

cool cool cool

CPhill Feb 4, 2016

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