+0  
 
0
2
1
avatar+737 

Find the number of ordered pairs $(a,b)$ of integers such that
\frac{a + 2}{a + 1} = \frac{b}{8}.

 Jan 10, 2024
 #1
avatar+126663 
+1

\(\frac{a + 2}{a + 1} = \frac{b}{8} \)

 

Rewrite  as

 

8(a + 2)  / (a + 1)  =  b

 

As a approaches  -infinity and  + infinity,  b  approaches 8

 

a         b

0       16

1       12

3       10

7        9

-2       0

-3       4

-5       6

-9       7

 

 

cool cool cool

 Jan 10, 2024

8 Online Users

avatar
avatar
avatar