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the number 101 can be written as the sum of 101 consecutive integers. What are the greatest and the smallest of those numbers?

 Aug 7, 2020
 #1
avatar+1038 
+5

To solve this, we need to first create an equation.

The equation will be n+(n+1)+(n+2)...+(n+99)+(n+100)=101

Combining like terms, we get 101n+5050=101

Isolate the n:

101n=-4949

n=-49

 

So, the smallest number is -49, and the largest is 51.

 

:)

 Aug 7, 2020
 #2
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0

OK sorry!

Guest Aug 7, 2020
edited by Guest  Aug 7, 2020
 #3
avatar+1038 
+5

I am a bit confused at what you mean n=-40.0891...

How is -4949/101=-40.0891? 

Maybe check your math...

 

P.S. Next time, maybe be a little nicer instead of saying "This screws up your answer"

 

:)

ilorty  Aug 7, 2020
 #4
avatar+28021 
+1

Ilorty is correct....    the    -49  thru -1   cancel out the   +1 thru + 49   and you are left with  50 + 51 = 101    sum of 101 integers (including zero)

 Aug 7, 2020

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