the number 101 can be written as the sum of 101 consecutive integers. What are the greatest and the smallest of those numbers?
+1084 To solve this, we need to first create an equation.
The equation will be n+(n+1)+(n+2)...+(n+99)+(n+100)=101
Combining like terms, we get 101n+5050=101
Isolate the n:
101n=-4949
n=-49
So, the smallest number is -49, and the largest is 51.
:)
+36916 Ilorty is correct.... the -49 thru -1 cancel out the +1 thru + 49 and you are left with 50 + 51 = 101 sum of 101 integers (including zero)
