the number 101 can be written as the sum of 101 consecutive integers. What are the greatest and the smallest of those numbers?

Guest Aug 7, 2020

#1**+5 **

To solve this, we need to first create an equation.

The equation will be n+(n+1)+(n+2)...+(n+99)+(n+100)=101

Combining like terms, we get 101n+5050=101

Isolate the n:

101n=-4949

n=-49

So, the smallest number is -49, and the largest is 51.

:)

ilorty Aug 7, 2020

#4**+1 **

Ilorty is correct.... the -49 thru -1 cancel out the +1 thru + 49 and you are left with 50 + 51 = 101 sum of 101 integers (including zero)

ElectricPavlov Aug 7, 2020