Find the number of ordered pairs $(a,b)$ of integers such that \frac{a + 2}{a + 1} = \frac{b}{8}.
\(\frac{a + 2}{a + 1} = \frac{b}{8} \)
8(a + 2) / ( a + 1) = b
a b
-9 7
-5 6
-3 4
-2 0
0 16
1 12
3 10
7 9
+479 
