Find the number of ordered pairs (a,b) of integers such that \frac{a + 2}{a + 1} = \frac{b}{8}.
a+2a+1=b8
8(a + 2) / ( a + 1) = b
a b
-9 7
-5 6
-3 4
-2 0
0 16
1 12
3 10
7 9
+478 
