Find four consecutive integers with the sum of 106
Let x be the first integer....and we have....
x + (x + 1) + (x + 2) + (x + 3) = 106 simplify
4x + 6 = 106 subtract 6 from both sides
4x = 100 divide both sides by 4
x = 25
So.....the intrgers are 25, 26, 27 and 28
