Dear mathlovers,

How do you evaluate this integral:\(\int{1}/{((A^2+B^2)^\frac{3}{2}) }dB \)

You have to use substitution somehow, but I don't know how to arrive at the point that you can.

Could you help me?

Kind regards,

David

Guest Oct 28, 2015

#5**+5 **

Alan: I plugged it into "WolframAlpha" engine!!. This is the result it gives. I'm not very good at Integral Calculus, so I cannot judge if the two are the same or not. They certainly look different:

http://www.wolframalpha.com/input/?i=integral+of+1%2F%28A%5E2%2BB%5E2%29%5E3%2F2+%28integrate+over+B%29.

If you cannot see the above link, here is their answer:1/(2 (A^2+B^2)^3)

Guest Oct 28, 2015

#7**0 **

Hi David,

If you are going to ask a few good questions like this why don't you join up so we can get to know you.

It is easier than posting as a guest all the time too. You only need to choose a username and a password, that is it!

Thanks Alan for that fabulous answer.

Chris sent the problem in a private message to make sure that i saw it, and that i would include it in my next wrap. :)

Chris worked through your answer and was very impressed by your logic.

Thanks for sending it to me Chris. :)

Melody Oct 29, 2015