Find the largest integral value of $x$ which solves: $\frac{1}{3}<{\frac{x}{5}}<{\frac{7}{8}}$
Breaking into parts
1/3 < x / 5 cross-multiply
5 / 3 < x so x > 5/3
Also
x / 5 < 7/8 cross-multiply
8x < 35
x < 35 / 8
The solution is 5 / 3 < x < 35 / 8
The largest integral value of x is 32 / 8 = 4
+816 
