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# Integrals

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259
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[-3.7,3.7]∫t/(t^6+5)=?

Thanks.

Guest Dec 6, 2014

#2
+26642
+5

The integrand, f(t) = t/(t6 + 5), is an odd function.  That is f(-t) = -f(t), so the integral between -3.7 and 0 exactly cancels the integral between 0 and +3.7, with the overall result of the integration being zero.

You can see this in the following image:

.

Alan  Dec 7, 2014
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#1
+5

You do appreciate that it is rather fearsome? http://m.wolframalpha.com/input/?i=integral+t%2F%28t%5E6%2B5%29&x=0&y=0

Good luck.

Guest Dec 6, 2014
#2
+26642
+5

The integrand, f(t) = t/(t6 + 5), is an odd function.  That is f(-t) = -f(t), so the integral between -3.7 and 0 exactly cancels the integral between 0 and +3.7, with the overall result of the integration being zero.

You can see this in the following image:

.

Alan  Dec 7, 2014
#3
+92256
0

#### That is really neat Alan :))

Melody  Dec 7, 2014

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