Integrals

Alan,

The question was written just like this $$(\ln(x))^2$$ EXCEPT  the exponent was before the variable and after the ln. Does this mean the same thing as what you have written?

The other part is correct though: $$\frac{1}{x(1+4etc.)}$$

Do you mean:

a)  $$(\ln(x))^2$$

or 

b) $$\ln{(x^2)}$$

and

c) $$\frac{1}{x(1+4etc.)}$$

or

d) $$\frac{(1+4etc.)}{x}$$

.