Evaluate the integral.
∫0−2(17x7+13x6−x)dx
0
(1/56)x^8 + (1/21)x^7 - (1/2)x^2 ] =
-2
- [ (1/56)x^8 + (1/21)x^7 - (1/2)x^2 ] =
- [ (1/56)(-2)^8 + (1/21)(-2)^7 - (1/2)(-2)^2 ] = 74/21 units^2
