Integrate 5x^2-5x+9 with respect to x

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Guest Nov 4, 2014

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Best Answer

Use the fact that $$\int{x^n}dx=\frac{x^{n+1}}{n+1}$$ as long as n ≠ -1.

So $$\int{(5x^2-5x+9)dx}=\frac{5x^3}{3}-\frac{5x^2}{2}+9x+k$$ where k is an arbitrary constant of integration.

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Alan Nov 4, 2014

Alan · Answer 1 · 2014-11-04T08:45:57

Use the fact that $$\int{x^n}dx=\frac{x^{n+1}}{n+1}$$ as long as n ≠ -1.

So $$\int{(5x^2-5x+9)dx}=\frac{5x^3}{3}-\frac{5x^2}{2}+9x+k$$ where k is an arbitrary constant of integration.

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