integration

$$\\w=\frac{-1}{-1/2cos(\theta^2)+(7/16)}\\\\
=-1\div \left(\frac{-1}{2cos(\theta^2)}+\frac{7}{16}\right)\\\\
=-1\div \left(\frac{-8}{16cos(\theta^2)}+\frac{7cos(\theta^2)}{16cos(\theta^2)}\right)\\\\
=-1\div \left(\frac{7cos(\theta^2)-8}{16cos(\theta^2)}\right)\\\\
=-1\times \left(\frac{16cos(\theta^2)}{7cos(\theta^2)-8}\right)\\\\
=\frac{16cos(\theta^2)}{8-7cos(\theta^2)}\\\\$$

Is that simple enough?     

Your pictures are not displaying for me.  

I can't see the images either.

Can you simplfy the following please.
$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)}$$

$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)}$$

firstly, do you mean

 $$\\(cos\theta)^2\;\;or\;\;cos(\theta^2)\\\\
note:\;\;cos^2\theta \;\;means\;\; (cos\theta)^2$$

sintheta ^2

h

Can you simplfy the following please

$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)}
=
\dfrac{-1}{-\dfrac{1}{2} \cos{
( \theta^2 )}
+\dfrac{7}{16}
}
=
\dfrac{-2}
{
\dfrac{7}{8}
-
\cos{
( \theta^2 )}
}
=
\dfrac{2}
{
\cos{
( \theta^2 )}
-
\dfrac{7}{8}
}$$

Heureka and I have interpreter it a little differently.

Heureka's answer is better.     

OK

I tink I it! What about you Stu?

Will let you know if the online test accepts either answer  j have a feeling it will and that I am really weak working with fractions like this. Also, there is a problem with mobile view/normal view on this site showing a large portion of the pagebin white and unable to zoom in to the section that is condesed to the lhs.

Hey, neither answer works, nor the step before the solution with the theta ^2 in side or outside the brackets.

Try monkeying around with it some more, Stu. You might get it. If not, there's still room in the bartending classes.

I'll help after I finish playing this game of chess. For my fee, fix me a drink. A banana daiquiri. May as well get started on your mixology skills.

Thanks anon,

Sorry Stu but this is really hilarious. 

You really should feel honoured.  No stranger has EVER paid me this much attention.   I haven't laughed so hard since anon's last post.

ROF LOL          

solved. thanks for the assit.