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# integration

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what is the methods used to solve both equations:

,   when  , in the form y(t)=

and

, in the form w(theta)=

thanks.

Stu  Sep 11, 2014

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$$\\w=\frac{-1}{-1/2cos(\theta^2)+(7/16)}\\\\ =-1\div \left(\frac{-1}{2cos(\theta^2)}+\frac{7}{16}\right)\\\\ =-1\div \left(\frac{-8}{16cos(\theta^2)}+\frac{7cos(\theta^2)}{16cos(\theta^2)}\right)\\\\ =-1\div \left(\frac{7cos(\theta^2)-8}{16cos(\theta^2)}\right)\\\\ =-1\times \left(\frac{16cos(\theta^2)}{7cos(\theta^2)-8}\right)\\\\ =\frac{16cos(\theta^2)}{8-7cos(\theta^2)}\\\\$$

Is that simple enough?

Melody  Sep 11, 2014
Sort:

#1
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Your pictures are not displaying for me.

Melody  Sep 11, 2014
#2
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I can't see the images either.

Alan  Sep 11, 2014
#3
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Can you simplfy the following please.
$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)}$$

Stu  Sep 11, 2014
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$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)}$$

firstly, do you mean

$$\\(cos\theta)^2\;\;or\;\;cos(\theta^2)\\\\ note:\;\;cos^2\theta \;\;means\;\; (cos\theta)^2$$

Melody  Sep 11, 2014
#5
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sintheta ^2

Stu  Sep 11, 2014
#6
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h

Stu  Sep 11, 2014
#7
+91465
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$$\\w=\frac{-1}{-1/2cos(\theta^2)+(7/16)}\\\\ =-1\div \left(\frac{-1}{2cos(\theta^2)}+\frac{7}{16}\right)\\\\ =-1\div \left(\frac{-8}{16cos(\theta^2)}+\frac{7cos(\theta^2)}{16cos(\theta^2)}\right)\\\\ =-1\div \left(\frac{7cos(\theta^2)-8}{16cos(\theta^2)}\right)\\\\ =-1\times \left(\frac{16cos(\theta^2)}{7cos(\theta^2)-8}\right)\\\\ =\frac{16cos(\theta^2)}{8-7cos(\theta^2)}\\\\$$

Is that simple enough?

Melody  Sep 11, 2014
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Can you simplfy the following please

$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)} = \dfrac{-1}{-\dfrac{1}{2} \cos{ ( \theta^2 )} +\dfrac{7}{16} } = \dfrac{-2} { \dfrac{7}{8} - \cos{ ( \theta^2 )} } = \dfrac{2} { \cos{ ( \theta^2 )} - \dfrac{7}{8} }$$

heureka  Sep 11, 2014
#9
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Heureka and I have interpreter it a little differently.

Melody  Sep 11, 2014
#10
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OK

I tink I it! What about you Stu?

Guest Sep 11, 2014
#11
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Will let you know if the online test accepts either answer  j have a feeling it will and that I am really weak working with fractions like this. Also, there is a problem with mobile view/normal view on this site showing a large portion of the pagebin white and unable to zoom in to the section that is condesed to the lhs.

Stu  Sep 11, 2014
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Hey, neither answer works, nor the step before the solution with the theta ^2 in side or outside the brackets.

Stu  Sep 22, 2014
#13
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Try monkeying around with it some more, Stu. You might get it. If not, there's still room in the bartending classes.

I'll help after I finish playing this game of chess. For my fee, fix me a drink. A banana daiquiri. May as well get started on your mixology skills.

Guest Sep 24, 2014
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Thanks anon,

Sorry Stu but this is really hilarious.

You really should feel honoured.  No stranger has EVER paid me this much attention.   I haven't laughed so hard since anon's last post.

ROF LOL

Guest Sep 25, 2014
#15
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solved. thanks for the assit.

Stu  Sep 29, 2014

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