what is the methods used to solve both equations:
, when , in the form y(t)=
and
(please solve the below question)
, in the form w(theta)=
thanks.
$$\\w=\frac{-1}{-1/2cos(\theta^2)+(7/16)}\\\\
=-1\div \left(\frac{-1}{2cos(\theta^2)}+\frac{7}{16}\right)\\\\
=-1\div \left(\frac{-8}{16cos(\theta^2)}+\frac{7cos(\theta^2)}{16cos(\theta^2)}\right)\\\\
=-1\div \left(\frac{7cos(\theta^2)-8}{16cos(\theta^2)}\right)\\\\
=-1\times \left(\frac{16cos(\theta^2)}{7cos(\theta^2)-8}\right)\\\\
=\frac{16cos(\theta^2)}{8-7cos(\theta^2)}\\\\$$
Is that simple enough?
$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)}$$
firstly, do you mean
$$\\(cos\theta)^2\;\;or\;\;cos(\theta^2)\\\\
note:\;\;cos^2\theta \;\;means\;\; (cos\theta)^2$$
$$\\w=\frac{-1}{-1/2cos(\theta^2)+(7/16)}\\\\
=-1\div \left(\frac{-1}{2cos(\theta^2)}+\frac{7}{16}\right)\\\\
=-1\div \left(\frac{-8}{16cos(\theta^2)}+\frac{7cos(\theta^2)}{16cos(\theta^2)}\right)\\\\
=-1\div \left(\frac{7cos(\theta^2)-8}{16cos(\theta^2)}\right)\\\\
=-1\times \left(\frac{16cos(\theta^2)}{7cos(\theta^2)-8}\right)\\\\
=\frac{16cos(\theta^2)}{8-7cos(\theta^2)}\\\\$$
Is that simple enough?
Can you simplfy the following please
$$w=\frac{-1}{-1/2cos(theta)^2+(7/16)}
=
\dfrac{-1}{-\dfrac{1}{2} \cos{
( \theta^2 )}
+\dfrac{7}{16}
}
=
\dfrac{-2}
{
\dfrac{7}{8}
-
\cos{
( \theta^2 )}
}
=
\dfrac{2}
{
\cos{
( \theta^2 )}
-
\dfrac{7}{8}
}$$
Heureka and I have interpreter it a little differently.
Heureka's answer is better.
Will let you know if the online test accepts either answer j have a feeling it will and that I am really weak working with fractions like this. Also, there is a problem with mobile view/normal view on this site showing a large portion of the pagebin white and unable to zoom in to the section that is condesed to the lhs.
Hey, neither answer works, nor the step before the solution with the theta ^2 in side or outside the brackets.
Try monkeying around with it some more, Stu. You might get it. If not, there's still room in the bartending classes.
I'll help after I finish playing this game of chess. For my fee, fix me a drink. A banana daiquiri. May as well get started on your mixology skills.