Help please. Need an explanation on how to do this, have a test tomorrow and don't understand.
∫(e^2x+1)/e^x dx
Thanks in advance
Do you mean
e^(2x+1) or e^(2x)+1 ?
\(\quad \int(e^{2x}+1)e^{-x}dx\\ =\int (e^x+e^{-x})dx\\ =e^x-e^{-x}+c\)
\(\quad \int(e^{2x+1})e^{-x}dx\\ =\int(e^{2x+1-x})dx\\ =\int(e^{x+1})dx\\ =\int(e*e^{x})dx\\ =e\int(e^{x})dx\\ =e*e^x+c\\ =e^{x+1}+c\)
