Why doesn't the natural log or Ln not have an integration yet you can get it from an integrated expression?
It does have an integration.......
∫ ln x dx
Let v = x dv = 1 dx u = ln x du = 1/x dx
So we have
∫ u dv = u * v - ∫ v du
∫ ln x (1) dx = ln x * x - ∫ x (1/x) dx
∫ ln x dx = x * ln x - ∫ 1 dx
∫ ln x dx = x * ln x - x + C
∫ ln x dx = x (ln x - 1) + C
+1491 
