I found this relation, with regards to predicting the number of digits of a kind of numbers:
I found that, when considering numbers, such that they are 4^(5n), i.e 4 raised to a multiple of 5, then the number of digits is always(for all numberis I tried, even 5^65) ' 3n + 1'
I was wondering if this is just a coincidence, or that there is some such relation with all numbers, when considering their exponentials, with the number of digits...
I hope my question is understood, coz its pretty hard for me to put this idea together... I'll give an example:
4^40 = 1 208 925 819 614 629 174 706 176 which is 25 digits.
40 = 5*8, which is of the form '5n' where n is 8
thus number of digits is 3n+1 i.e 3*8 + 1 = 25...
