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In triangle HIJ, HJ is extended through point J to point K, angle IJK = (7x - 15), angle JHI = (3x + 18), and angle HIJ = (x + 6).  Find angle JHI.

 

 Feb 28, 2021
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HIJ+JHI+IJH=x+6+3x+18+180-(7x-15)=-3x+219=180

3x=219-180=39

x=13

 

JHI=3x+18=39+18=$\boxed{57}$

 Mar 2, 2021

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