What is the area, in square units, of the interior region formed by the lines y = 4x - 6, y = -2x + 8, and the y-axis?
What is the area, in square units, of the interior region formed by the lines y = 4x - 6, y = -2x + 8, and the y-axis?
Hello Guest!
\(y=4x-6\\ y=-2x+8\)
\(4x-6=-2x+8\\ 6x=14\\ \color{blue}x=\frac{7}{3}\)
\(A=\frac{1}{2}\cdot (8+6)\cdot \frac{7}{3}\)
\(A=\frac{49}{3}\ square\ units\)
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