inverse function of log6(x+1)

nverse function of log6(x+1)

----------------------------------------------------------------------------------------------------------------------------

I'm assuming that you mean this:   y = log₆ (x + 1)

Let's write this in exponential form, we have

6^y = (x + 1)           Now get x by itself

6^y - 1  = x              Now "exhange" x and y

6^x - 1  = y              Now, write y  as f^-1(x)

f^-1(x) = 6^x - 1

Notice that the "log" graph has a restricted domain ......i.e., x > -1

And notice that the range of the inverse is y (or f^-1(x))  > -1