Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
679
1
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x f(x)
1 3
2 1
3 5
4 4
5 2

 

The values of a function f(x) are given in the table above.
 

If f^{-1} exists, then what is f^{-1}(f^{-1}(f^{-1}(1)))?

 Feb 7, 2018
 #1
avatar+130466 
+1

f-1  does exist

 

 

 f^{-1}(f^{-1}(f^{-1}(1)))  =

 

(  f-1  °    f -1   °   f-1 ) (1)  =

 

( f-1 °  f -1) (2)  =

 

f-1 ( 5)  =

 

3

 

 

cool cool cool

 Feb 7, 2018
edited by CPhill  Feb 7, 2018

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