I need help...
The values of a function \(f(x)\) are given in the table below.
If \(f^{-1}\) exists, then what is \(f^{-1}(f^{-1}(f^{-1}(1)))\)?
We actually have the coordinates ( 1,3) (2,1) (3.5) (4,4) (5,2)
The inverse reverses these so we would have ( 3,1) (1,2) ( 5,3) (4,4) (2,5)
So f-1(1) = 2
And f-1 ( f-1(1)) = f-1(2) = 5
Finally
f-1 ( f-1 (f-1 (1) )) = f-1(5) = 3
