If $h(y)=\dfrac{1+y}{2-y}$, then what is the value of $h^{-1}(5)$? Express your answer in simplest form.
We can solve this
5 = (1 + y) / ( 2 - y) cross-mulriply
5 ( 2 - y) = 1 + y
10 - 5y = 1 + y
10 - 1 = y + 5y
9 = 6y
y = 9/6 = 3/2 = h-1 (5)
+184 
