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If h(y) = (1 + y)/(2 + y), then what is the value of $h^{-1}(5)$?  Express your answer in simplest form.

 Apr 17, 2021
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X = (y+1)/(y+2)   to get the inverse, switch x's and y 's then solve for x

y = (x+1)/(x+2)

(x+2)y =  x+1

xy + 2y -x = 1

x ( y-1) = 1 - 2y

x = (1-2y)/(y-1)       is the inverse       h-1 (5) = -9/4  =  - 2 1/4

 Apr 17, 2021
edited by ElectricPavlov  Apr 17, 2021

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