Inverse Functions

ElictricPavlov already answered this but this is what he said "

X = (y+1)/(y+2)   to get the inverse, switch x's and y 's then solve for x

y = (x+1)/(x+2)

(x+2)y =  x+1

xy + 2y -x = 1

x ( y-1) = 1 - 2y

x = (1-2y)/(y-1)       is the inverse       h-1 (5) = -9/4  =  - 2 1/4

"

(y, 5)  is  on  the original function

So   (5, y)  is  on the  inverse

So  ....We  can solve this

5  =  (1 + y)  / (2 + y)

5 (2 + y)  =  1 + y

10  + 5y  =  1 + y

5y - y =  1  -10

4y  = -9

y  = -9/4  =  h^-1(5)