The values of a function $f(x)$ are given below:
Evaluate $f^{-1}\left(f^{-1}(50)\times f^{-1}(10)+f^{-1}(26)\right)$.
f-1 (50)= 7
f-1 (10) = 3
f-1 ( 26) = 5
So we have
f-1 ( 7 * 3 + 5) = f-1 (26) = 5