Define $f(x)=3x-8$. If $f^{-1}$ is the inverse of $f$, find the value(s) of $x$ for which $f(x)=f^{-1}(x)$.
Find the inverse.....
x = 3y-8 y = (x+8) / 3 this is the inverse.....equate it to the original and solve fo x
(x+8) / 3 = 3x-8 Now solve for 'x' to find the value(s) where f(x) = f-1 (x)