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If h(y) = (1 + y)/(2 - 2y), then what is the value of $h^{-1}(5)$?  Express your answer in simplest form.

 Jun 15, 2021
 #1
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h-1 (5)   means  that

 

5 =   ( 1 + y)  / ( 2 - 2y)

 

5 ( 2 - 2y)   =  1 +  y      simplify

 

10  -  10y   =   1 + y

 

10 - 1   =   10y +  y

 

9  =  11y

 

y  = 9 / 11    =   h-1 (5)

 

 

cool cool cool

 Jun 15, 2021

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