If h(y) = (1 + y)/(2 - 2y), then what is the value of $h^{-1}(5)$? Express your answer in simplest form.
h-1 (5) means that
5 = ( 1 + y) / ( 2 - 2y)
5 ( 2 - 2y) = 1 + y simplify
10 - 10y = 1 + y
10 - 1 = 10y + y
9 = 11y
y = 9 / 11 = h-1 (5)
