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If f(x) = 16/(5 + 3x), what is the value of $f^{-1}(-2)$?

 Nov 6, 2021
 #1
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 y=16/(5+3x)

 

inverse

 

x=16/(5-3y)

 

-2= 16/(5-3y)

-2(5-3y)=16

3y-5 = -8

3y = -3

y=-1

 

\(f^{-1}(-2)=-1\)

 Nov 8, 2021

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