If f(x) = 16/(5 + 3x), what is the value of $f^{-1}(-2)$?
y=16/(5+3x)
inverse
x=16/(5-3y)
-2= 16/(5-3y)
-2(5-3y)=16
3y-5 = -8
3y = -3
y=-1
\(f^{-1}(-2)=-1\)
