+0

# Inverse functions

0
39
3

If f(x)=x^3+3x^2+3x+1, find f^{-1}(2).

Jul 22, 2022

### Best Answer

#2
+197
+1

There is a way to find the exact value! :D

x^3 + 3x^2 + 3x + 1 = 2

(x+1)^3 = 2

x = $$\sqrt[3]{2}-1$$

Jul 22, 2022

### 3+0 Answers

#1
+117758
+1

$$x^3+3x^2+3x+1=2\\ x^3+3x^2+3x-1=0\\ x\approx 0.26$$

.
Jul 22, 2022
#2
+197
+1
Best Answer

There is a way to find the exact value! :D

x^3 + 3x^2 + 3x + 1 = 2

(x+1)^3 = 2

x = $$\sqrt[3]{2}-1$$

Voldemort Jul 22, 2022
#3
+117758
0

Thanks Voldemort

Melody  Jul 22, 2022