Inverse Matrices

Here's the formula, Strider

The inverse of a 3x3 matrix:

| a11 a12 a13 |-1 | a33a22-a32a23 -(a33a12-a32a13) a23a12-a22a13 | | a21 a22 a23 | = 1/DET * | -(a33a21-a31a23) a33a11-a31a13 -(a23a11-a21a13) | | a31 a32 a33 | | a32a21-a31a22 -(a32a11-a31a12) a22a11-a21a12 | with DET = a11(a33a22-a32a23)-a21(a33a12-a32a13)+a31(a23a12-a22a13)

Can you do it, now...or do you need some help??? It's really just a "plug and play" problem....but kinda' lengthy...let me know

   

thanks! i figured it out!