Given that f(3)=5 and \(f(3x)=f(x)+2\) for all x, find \(f^{-1}(11)\).
The answer is 81
you can see every time we multiply x by 3, the y goes up by 2
so 11-5=6
6/2=3
3^1*3^3=3^4=81
(This question a little chanellge to me. Difinitely fun!)
The first anwser is right,but I think my anwser is more specific.
given f(3)=5
f(9)=f(3)+2=5+2=7
f(27)=f(9)+2=7+2=9
f(81)=f(27)+2=9+2=11
\({f}^{-1}(11)={f}^{-1}(f(81))=81\)