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whats the inverse y=2x^2-3??

 Apr 9, 2020
 #1
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+1

The  object is  to get  x by itself  and  then "switch" x  and  y......we can write

 

y = 2x^2  - 3      add  3 to both sides

 

y + 3  =   2x^2      divide both sides  by  2

 

[ y + 3 ] / 2    =  x^2         take both roots

 

±√ [ (y + 3) / 2 ]  =  x   "switch" x and y

 

±√ [ ( x + 3)  / 2  ]  =  y   =  the inverse

 

 

cool cool cool

 Apr 9, 2020

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