+0  
 
0
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avatar+176 

Each digit in the number 2001 is placed on a different card. In how many ways can three different cards be selected so that the product of the numbers on those cards is not zero?

 Oct 24, 2018
 #1
avatar+94545 
+2

You are correct, ANSP  !!!!

 

At least one card  must contain a "0"....so....the product will be  0

 

So...there are no ways in which this is possible...

 

 

cool cool cool

 Oct 24, 2018

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