+0  
 
0
1000
1
avatar+283 

Each digit in the number 2001 is placed on a different card. In how many ways can three different cards be selected so that the product of the numbers on those cards is not zero?

 Oct 24, 2018
 #1
avatar+128055 
+2

You are correct, ANSP  !!!!

 

At least one card  must contain a "0"....so....the product will be  0

 

So...there are no ways in which this is possible...

 

 

cool cool cool

 Oct 24, 2018

4 Online Users

avatar
avatar