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Is pi divisible by anything

 Jun 9, 2015

Best Answer 

 #2
avatar+118587 
+13

Hi Dragonlance,

 

It means that if you graph

 

$$y=a_1x^n+a_2x^{n-1}+a_3x^{n-2}+.................a_{n+1}$$

 

Where n is a positive integer and

where all the coefficients are rational numbers

and a_1 is not 0

 

That the graph can never cut the x axis at  $$\pi$$

 

(I don't know why not, but that is an explanation of what you just said)

 Jun 9, 2015
 #1
avatar+1315 
+5

Pi is a real number it is divisable by any other real number. You can not make it a fraction because it is irrational.

It is also a transcendental number that means is not a root of a non-zero polynomial equation with rational coefficients. I find that on the net but I dont know what it means.

Melody can you explaine it? Please.

 Jun 9, 2015
 #2
avatar+118587 
+13
Best Answer

Hi Dragonlance,

 

It means that if you graph

 

$$y=a_1x^n+a_2x^{n-1}+a_3x^{n-2}+.................a_{n+1}$$

 

Where n is a positive integer and

where all the coefficients are rational numbers

and a_1 is not 0

 

That the graph can never cut the x axis at  $$\pi$$

 

(I don't know why not, but that is an explanation of what you just said)

Melody Jun 9, 2015
 #3
avatar+1315 
0

Thank you Melody. I knew this was complicated and it will be a long time before I understand it.

 

I know that finding roots and findig zeros are the same thing. This becaue the y part is zero when the x is equal to something.  So the y can never be zero when the x part equal Pi. right?

 

Is the equation for a parabola a polynomial equation or is it something else? I think it is something else because it look like you can make one where it cross the x at Pi when y = 0. I will try to make one but I not sure I know how.

 Jun 9, 2015
 #4
avatar+118587 
+8

A parabola is a polynomial because it can be written in the form y=ax^2+bx+c

 

$$\\y= x^2-\pi x\;\;\;\;$ will have a root at $\pi\\\\
$but the coefficient of x is irrational so it does not contradict the prior statement$$$

 Jun 9, 2015

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