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is the cot(pi) non conclusive

 Aug 12, 2015

Best Answer 

 #1
avatar+118608 
+5

Here is a graph of     $$y=cot\theta$$

 

The blue line is where    $$\theta = \pi$$

 

You can see that 

 

$$\\\displaystyle\lim_{x\rightarrow\pi\;from\; below}=-\infty\\\\
and\\\\
\displaystyle\lim_{x\rightarrow\pi\;from\; above}=+\infty\\\\
$So yes $cot(\pi) $ is indeterminant.$$$

 

 

 

ALSO there is another way to look at it.

 

$$\\cot(\pi)=\frac{cos(\pi)}{sin(\pi)}=\frac{-1}{0}$$

 

but you cannot divide by zero so this is indeterminant.

 Aug 12, 2015
 #1
avatar+118608 
+5
Best Answer

Here is a graph of     $$y=cot\theta$$

 

The blue line is where    $$\theta = \pi$$

 

You can see that 

 

$$\\\displaystyle\lim_{x\rightarrow\pi\;from\; below}=-\infty\\\\
and\\\\
\displaystyle\lim_{x\rightarrow\pi\;from\; above}=+\infty\\\\
$So yes $cot(\pi) $ is indeterminant.$$$

 

 

 

ALSO there is another way to look at it.

 

$$\\cot(\pi)=\frac{cos(\pi)}{sin(\pi)}=\frac{-1}{0}$$

 

but you cannot divide by zero so this is indeterminant.

Melody Aug 12, 2015

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