Here is a graph of $$y=cot\theta$$
The blue line is where $$\theta = \pi$$
You can see that
$$\\\displaystyle\lim_{x\rightarrow\pi\;from\; below}=-\infty\\\\
and\\\\
\displaystyle\lim_{x\rightarrow\pi\;from\; above}=+\infty\\\\
$So yes $cot(\pi) $ is indeterminant.$$$
ALSO there is another way to look at it.
$$\\cot(\pi)=\frac{cos(\pi)}{sin(\pi)}=\frac{-1}{0}$$
but you cannot divide by zero so this is indeterminant.
Here is a graph of $$y=cot\theta$$
The blue line is where $$\theta = \pi$$
You can see that
$$\\\displaystyle\lim_{x\rightarrow\pi\;from\; below}=-\infty\\\\
and\\\\
\displaystyle\lim_{x\rightarrow\pi\;from\; above}=+\infty\\\\
$So yes $cot(\pi) $ is indeterminant.$$$
ALSO there is another way to look at it.
$$\\cot(\pi)=\frac{cos(\pi)}{sin(\pi)}=\frac{-1}{0}$$
but you cannot divide by zero so this is indeterminant.