Amy has 5 dollars in quarters, dimes and nickels, where the total value in quarters is more than the total value of the dimes, and the total value of the dimes is more than the total value of the nickels. What is the maximun amount of coins Amy could have.

Tervvy Apr 11, 2020

#1**0 **

I think the following will you the maximum numbers of coins:

1 - 13 quarters x 0.25 = $3.25

$5.00 - $ 3.25 = $1.75 left

2 - 12 dimes x 0.10 = $1.20

$1.75 - $1.20 =$ 0.55 left

3 - 11 nickels x 0.05 =$ 0.55

$0.55 - $0.55 = 0 left.

4 - So, you can have a maximum of: 13 quarters + 12 dimes + 11 nickels = $5

Guest Apr 11, 2020