+128732 [9x^ + 12x + 4] /[12x^2 + 5x -2] * [16x^2 -1] / [4x^2 + 5x + 1] factor
[(3x + 2)(3x + 2)] / [(4x- 1)(3x + 2)] * [(4x + 1)(4x -1)] / [(4x + 1)(x + 1)] "cancel" where possible
(3x + 2)/(4x -1) * (4x -1)/(x + 1) =
(3x + 2) / (x + 1)
{ I think you only made a slight mistake in factoring [9x^2 + 12x + 4] }
Thank you.
I think I made a mistake in this one also. It was a bit difficult. Can you check it please.
My answer is = (x + 9) / (x + 2)
+128732 [x^2 -25] / [x^2 - 10x + 25] * [x^2 - 7x + 10] / [x^2 - x -2] + 1/[x + 1]
Factor and "cancel" where possible
[(x + 5)(x -5)]/ [(x -5)(x -5)] * [(x -5)(x - 2)]/[ (x -2)(x + 1)] + 1 /[x + 1]
(x + 5)/(x-5) * (x -5)/(x + 1) + 1 /(x + 1)
(x + 5)/(x + 1) + 1/(x + 1) =
(x + 5 + 1) /(x + 1) =
(x + 6) / (x + 1)
{Remember.....the inclination is to want to combine the last two fractions, first......however, this is incorrect......the multiplied fractions are done before any adding/subtracting takes place....... }
These equations confuse me. I apreciate your help and explanations.
However I still have 3 questions left lol
+128732 OK....try to work them yourself, first......if you get stuck ..... post them....and I'll take a look....
1. 
My answer = (3x+1/ 2x+1)
2.
My answer = (a - 3) / (a - 5)
3. 
My answer was the same as the question = (-5/8) - (3/2y)
+128732 3. -5/8 - 3/[2y]
Note that the common denominator is just 8y....so we have
[-5(y) - 3(4)] / [2y] =
-[5y + 12] / [2y]
2. [a - 1]/[a -2] - [3a -1] / [a^2 + 3a - 10] factor, where necessary
[a-1] / [a - 2] - [3a - 1 ] / [(a + 5)(a -2)] notice that we need (a + 5) in the first fraction
[(a - 1)(a + 5) - (3a -1) / [(a + 5)(a -2)] =
[a^2 + 4a - 5 - 3a + 1]/ [(a + 5)(a - 2)] =
[a^2 + a - 4] / [(a + 5)(a -2)]
1. [4w + 8] / [w^2 - w - 6] * [w^3 - 3w^2] / [8w^2 - 8w] factor
4[w + 2] / [(w -3)(w + 2)] * [w^2 (w -1)] / [8w(w -1)] =
4/(w - 3) * (w^2)/(8w) =
w / [2(w -3)]
