+0  
 
0
349
2
avatar+10 

Hello I have a new question! 

 

The question is (originally written in swedish): 

Divide Factors: 64x^4-4x^2

My answer: 4x^2(16x^2-1)

Mozziee  Jul 27, 2014

Best Answer 

 #2
avatar+92254 
+10

Thanks Alan, I just explain a little further,

 

$$\\(a-b)(a+b)=a^2+ab-ab-b^2=a^2-b^2\\\
so

\boxed{a^2-b^2=(a-b)(a+b)}\\\\

\mbox{This is referred to as a difference of two squares and you need to memorize it.}\\\\

\begin{array}{rll}
16x^2-1&=&(4x)^2-1^2\\\\
&=&(4x-1)(4x+1)
\end{array}$$

Melody  Jul 27, 2014
Sort: 

2+0 Answers

 #1
avatar+26642 
+10

Yes, though you can take it a little further to get:  4x^2(4x+1)(4x-1)

So the factors are: 4, x^2, 4x+1 and 4x-1 (and various combinations of these).

Alan  Jul 27, 2014
 #2
avatar+92254 
+10
Best Answer

Thanks Alan, I just explain a little further,

 

$$\\(a-b)(a+b)=a^2+ab-ab-b^2=a^2-b^2\\\
so

\boxed{a^2-b^2=(a-b)(a+b)}\\\\

\mbox{This is referred to as a difference of two squares and you need to memorize it.}\\\\

\begin{array}{rll}
16x^2-1&=&(4x)^2-1^2\\\\
&=&(4x-1)(4x+1)
\end{array}$$

Melody  Jul 27, 2014

44 Online Users

avatar
avatar
avatar
avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details