+10 Hello I have a new question!
The question is (originally written in swedish):
Divide Factors: 64x^4-4x^2
My answer: 4x^2(16x^2-1)
+118608 Thanks Alan, I just explain a little further,
$$\\(a-b)(a+b)=a^2+ab-ab-b^2=a^2-b^2\\\
so
\boxed{a^2-b^2=(a-b)(a+b)}\\\\
\mbox{This is referred to as a difference of two squares and you need to memorize it.}\\\\
\begin{array}{rll}
16x^2-1&=&(4x)^2-1^2\\\\
&=&(4x-1)(4x+1)
\end{array}$$
+33614 Yes, though you can take it a little further to get: 4x^2(4x+1)(4x-1)
So the factors are: 4, x^2, 4x+1 and 4x-1 (and various combinations of these).
+118608 Thanks Alan, I just explain a little further,
$$\\(a-b)(a+b)=a^2+ab-ab-b^2=a^2-b^2\\\
so
\boxed{a^2-b^2=(a-b)(a+b)}\\\\
\mbox{This is referred to as a difference of two squares and you need to memorize it.}\\\\
\begin{array}{rll}
16x^2-1&=&(4x)^2-1^2\\\\
&=&(4x-1)(4x+1)
\end{array}$$
