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Hello I have a new question! 

 

The question is (originally written in swedish): 

Divide Factors: 64x^4-4x^2

My answer: 4x^2(16x^2-1)

Mozziee  Jul 27, 2014

Best Answer 

 #2
avatar+94120 
+10

Thanks Alan, I just explain a little further,

 

$$\\(a-b)(a+b)=a^2+ab-ab-b^2=a^2-b^2\\\
so

\boxed{a^2-b^2=(a-b)(a+b)}\\\\

\mbox{This is referred to as a difference of two squares and you need to memorize it.}\\\\

\begin{array}{rll}
16x^2-1&=&(4x)^2-1^2\\\\
&=&(4x-1)(4x+1)
\end{array}$$

Melody  Jul 27, 2014
 #1
avatar+27229 
+10

Yes, though you can take it a little further to get:  4x^2(4x+1)(4x-1)

So the factors are: 4, x^2, 4x+1 and 4x-1 (and various combinations of these).

Alan  Jul 27, 2014
 #2
avatar+94120 
+10
Best Answer

Thanks Alan, I just explain a little further,

 

$$\\(a-b)(a+b)=a^2+ab-ab-b^2=a^2-b^2\\\
so

\boxed{a^2-b^2=(a-b)(a+b)}\\\\

\mbox{This is referred to as a difference of two squares and you need to memorize it.}\\\\

\begin{array}{rll}
16x^2-1&=&(4x)^2-1^2\\\\
&=&(4x-1)(4x+1)
\end{array}$$

Melody  Jul 27, 2014

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