Find three consecutive integers such that twice the greatest integer is 3 less than 3 times the least integer
+26367 Find three consecutive integers such that twice the greatest integer is 3 less than 3 times the least integer
Three consecutive integers: \((n-1),\ n,\ (n+1)\)
Twice the greatest integer is 3 less than 3 times the least integer:
\(\begin{array}{|rcll|} \hline 2(n+1) &=& 3(n-1)-3 \\ 2n+2 &=& 3n-3-3 \\ 2n+2 &=& 3n-6 \\ 2n+8 &=& 3n \\ 8 &=& 3n-2n \\ 8 &=& n \\ \mathbf{n} &=& \mathbf{8} \\ \hline \end{array}\)
The three consecutive integers are: \(\mathbf{7,\ 8,\ 9}\)
