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lg2(x+3)-lg2(x-6)=1+lg2(x-2)-lg2(x-4)
 Nov 5, 2013
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I asssume lg2 means log base 2 that is log 2

http://en.wikipedia.org/wiki/List_of_logarithmic_identities

lg2(x+3)-lg2(x-6)=1+lg2(x-2)-lg2(x-4)

lg2(x+3)-lg2(x-6)-lg2(x-2)+lg2(x-4) =1

lg 2 { [(x+3)(x-4)] / [(x-6)(x-2)] } = lg 2(2)

[(x+3)(x-4)] / [(x-6)(x-2)] = 2

etc
 Nov 5, 2013

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