A isosceles trapezoid has bases \(AB=15\) and \(CD=20\). Points \(E\) and \(F\) are on \(AD\) and \(BC\) respectively such that \(EF\parallel AB\). If \(AE:ED=2:3\), compute \(EF\).
EF = 2(2*sin30º) + 15 = 17
Where did you get 30 degrees from?
Here is my take.
I have added a couple of points.
\(\frac{TE}{2x}=\frac{2.5}{5x}\\ TE=1\\ FE=1+15+1=17 units\)
A quicker way to look at it is that the difference between 15 and 20 is 5.
EF is 2/5 of the way from the short side.
2/5 of 5 = 2
so the length of EF will be 15+2 =17 units
