The lengths of the sides of isosceles triangle triangle ABC$ are 3x+62, 7x+60, and 5x+50 feet. What is the least possible number of feet in the perimeter of triangle ABC?
Either
3x + 62 = 7x + 60
4x = 2
x = 2/4 = 1/2
Or
7x + 60 = 5x + 50
7x - 5x = 50 -60
2x = -10
x = -5
3x + 62 = 5x + 60
62 -60 = 5x - 3x
2 = 2x
x = 1
The perimeter is minimized when x = - 5
48 + 25 + 25 =
98 ft
