The lengths of the sides of isosceles triangle ABC are 3x + 62, 7x + 30, and 5x + 60 feet. What is the least possible number of feet in the perimeter of ABC?
Isoc triangle so two of the sides are equal either
3x+62 = 5x+60 then x = 1
3x+62= 7x + 30 then x = 8
7x+30 = 5x + 60 then x = 15 the value of 'x' which will produce the smallest perimeter is x = 1 You can finish......