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$\triangle ABC$ is an isosceles triangle. $\angle C = 90^\circ.$  Find the sum of all possible values of $\angle B,$ in degrees.

 Dec 20, 2023
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If isosceles, AC = BC

So....angle  CAB = angle CBA

Since angle ACB (angle C) = 90°

Then the only possible value for  angle CBA (angle B)  is 45°

 

cool cool cool

 Dec 20, 2023

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